第二十五组-马毅铎-兰宏程-张嘉伦-潘浩伟-王嘉佟.zip 444.67KB

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第二十五组-马毅铎-兰宏程-张嘉伦-潘浩伟-王嘉佟.zip 大约有3个文件

第二十五组-马毅铎-兰宏程-张嘉伦-潘浩伟-王嘉佟/第二十五组答辩课件.pptx 558.69KB
第二十五组-马毅铎-兰宏程-张嘉伦-潘浩伟-王嘉佟/第二十五组课程设计.docx 58.1KB
第二十五组-马毅铎-兰宏程-张嘉伦-潘浩伟-王嘉佟/爬楼梯.py 1.11KB

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第二十五组-马毅铎-兰宏程-张嘉伦-潘浩伟-王嘉佟.zip

<link href="/image.php?url=https://csdnimg.cn/release/download_crawler_static/css/base.min.css" rel="stylesheet"/><link href="/image.php?url=https://csdnimg.cn/release/download_crawler_static/css/fancy.min.css" rel="stylesheet"/><link href="/image.php?url=https://csdnimg.cn/release/download_crawler_static/89542011/raw.css" rel="stylesheet"/><div id="sidebar" style="display: none"><div id="outline"></div></div><div class="pf w0 h0" data-page-no="1" id="pf1"><div class="pc pc1 w0 h0"><img alt="" class="bi x0 y0 w1 h1" src="/image.php?url=https://csdnimg.cn/release/download_crawler_static/89542011/bg1.jpg"/><div class="t m0 x1 h2 y1 ff1 fs0 fc0 sc0 ls0 ws0">2023<span class="_ _0"> </span><span class="ff2">级“大学计算机基础”</span></div><div class="t m0 x2 h2 y2 ff2 fs0 fc0 sc0 ls0 ws0">课程设计报告</div><div class="c x3 y3 w2 h3"><div class="t m0 x4 h4 y4 ff3 fs1 fc0 sc0 ls0 ws0">单<span class="_ _1"> </span>位</div></div><div class="c x5 y3 w3 h3"><div class="t m0 x6 h4 y5 ff3 fs1 fc0 sc0 ls0 ws0">学院一大队学院三队</div></div><div class="c x3 y6 w2 h5"><div class="t m0 x4 h4 y4 ff3 fs1 fc0 sc0 ls0 ws0">组<span class="_ _2"> </span>号</div></div><div class="c x5 y6 w3 h3"><div class="t m0 x7 h4 y5 ff3 fs1 fc0 sc0 ls0 ws0">第二十五组</div></div><div class="c x5 y7 w3 h6"><div class="t m0 x8 h4 y5 ff4 fs1 fc0 sc0 ls0 ws0">234103095 <span class="ff3">马毅铎</span></div></div><div class="c x5 y8 w3 h6"><div class="t m0 x8 h4 y5 ff4 fs1 fc0 sc0 ls0 ws0">234103121 <span class="ff3">张嘉伦</span></div></div><div class="c x5 y9 w3 h6"><div class="t m0 x8 h4 y5 ff4 fs1 fc0 sc0 ls0 ws0">234103069 <span class="ff3">潘浩伟</span></div></div><div class="c x5 ya w3 h6"><div class="t m0 x8 h4 y5 ff4 fs1 fc0 sc0 ls0 ws0">234103080 <span class="ff3">王嘉佟</span></div></div><div class="c x3 yb w2 h7"><div class="t m0 x4 h4 yc ff3 fs1 fc0 sc0 ls0 ws0">组<span class="_ _2"> </span>员</div></div><div class="c x5 yd w3 h6"><div class="t m0 x8 h4 y5 ff4 fs1 fc0 sc0 ls0 ws0">234103124 <span class="ff3">兰宏程</span></div></div><div class="c x3 ye w2 h5"><div class="t m0 x4 h4 y4 ff3 fs1 fc0 sc0 ls0 ws0">题<span class="_ _3"></span>目<span class="_ _3"></span>编<span class="_ _3"></span>号</div></div><div class="c x5 ye w3 h3"><div class="t m0 x7 h4 y5 ff3 fs1 fc0 sc0 ls0 ws0">第九十三题</div></div><div class="t m0 x9 h8 yf ff5 fs2 fc0 sc0 ls0 ws0">二〇二四年七月十四日<span class="ff6 fs3"> </span></div><div class="t m0 xa h9 y10 ff7 fs4 fc0 sc0 ls0 ws0">一、<span class="_ _4"></span>问题描述</div><div class="t m0 xb h4 y11 ff3 fs1 fc0 sc0 ls0 ws0">假设<span class="_ _4"></span>你<span class="_ _4"></span>正<span class="_ _4"></span>在爬<span class="_ _4"></span>梯<span class="_ _4"></span>子<span class="_ _4"></span>，梯<span class="_ _4"></span>子<span class="_ _4"></span>一<span class="_ _4"></span>共有<span class="_ _5"> </span><span class="ff4">n<span class="_ _5"> </span></span>阶。每<span class="_ _4"></span>次<span class="_ _4"></span>你可<span class="_ _4"></span>以<span class="_ _4"></span>爬<span class="_ _5"> </span><span class="ff4">1<span class="_ _6"> </span></span>或<span class="_ _6"> </span><span class="ff4">2<span class="_ _6"> </span></span>个</div><div class="t m0 xb h4 y12 ff3 fs1 fc0 sc0 ls0 ws0">台阶<span class="_ _4"></span>，<span class="_ _4"></span>试<span class="_ _4"></span>问你<span class="_ _4"></span>有<span class="_ _4"></span>多<span class="_ _4"></span>少种<span class="_ _4"></span>不<span class="_ _4"></span>同<span class="_ _4"></span>的方<span class="_ _4"></span>法<span class="_ _4"></span>可<span class="_ _4"></span>以爬<span class="_ _4"></span>到<span class="_ _4"></span>楼<span class="_ _4"></span>顶呢<span class="_ _4"></span>？<span class="_ _4"></span>并<span class="_ _4"></span>给出<span class="_ _4"></span>每</div><div class="t m0 xb h4 y13 ff3 fs1 fc0 sc0 ls0 ws0">种方法的具体步骤。</div></div><div class="pi" data-data='{"ctm":[1.611830,0.000000,0.000000,1.611830,0.000000,0.000000]}'></div></div><div id="pf2" class="pf w0 h0" data-page-no="2"><div class="pc pc2 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="/image.php?url=https://csdnimg.cn/release/download_crawler_static/89542011/bg2.jpg"><div class="t m0 xa h9 y14 ff7 fs4 fc0 sc0 ls0 ws0">二、设计思路</div><div class="t m0 xc h4 y15 ff3 fs1 fc0 sc0 ls0 ws0">主要采<span class="_ _4"></span>用了迭代<span class="_ _4"></span>和穷举<span class="_ _4"></span>的思想<span class="_ _4"></span>，定义<span class="_ _4"></span>了递归<span class="_ _4"></span>函数，<span class="_ _4"></span>从初始<span class="_ _4"></span>值开始，</div><div class="t m0 xc h4 y16 ff3 fs1 fc0 sc0 ls0 ws0">将所有满足条件的路径以列表的方式，<span class="_ _7"></span>使用<span class="_ _6"> </span><span class="ff4">append<span class="_ _6"> </span></span>函数储存在一</div><div class="t m0 xc h4 y17 ff3 fs1 fc0 sc0 ls0 ws0">个空列表中。所以此列表中所有列表的个数即总的路径数。</div></div><div class="pi" data-data='{"ctm":[1.611830,0.000000,0.000000,1.611830,0.000000,0.000000]}'></div></div>

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